Question

hey mate......here is your question
Q-find the value of y for which the distance between the point P(2,-3) and Q(10,y) is 10 units...

have a great day :)

Answer 1

$\:\: \underline{\underline{\bf{\large\mathfrak{~~solution~~}}}}$

$\sqrt{(2 - 10) {}^{2} + ( - 3 - y) {}^{2} } = 10 \\ = > 64 + ( - 3 - y) {}^{2} = 100 \\ = > ( - 3 - y) {}^{2} = 36 \\ = > ( - 3 - y) {}^{2} = 6 {}^{2} \\ = > - 3 - y = 6 \\ = > y = 3$

Answer 2

Answer:

jaaao na pgl mujhe nhi ataa