hey mate here your answer
find the solution of x+2y=10 and 2x+4y=8 graphically
iknow that u can't type a graphic so do the soloution plz
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Answered by
3
x +2y = 4
2y= -x+4
y = -1/2x + 2 the slope is -1/2 and the y-intercept is 2.
2x + 4y = 8
4y = -2x + 8
y = -2/4 x +2
y= -1/2 x +2 the slope for this equation is also -1/2 and the
y-intercept is also 2.
If we try to graph these "two" line we quickly see that they are, in fact, the same line, where there is not one point of interception, but rather, all points are common to both.
When graphing the solution to a system of first degree equations like these, there are three possible outcomes. They will intercept at one point (x,y); or, as in this case, they are the same equation and all points are common; or the lines are parallel, they have the same slope but a different y-intercept, and they have no point of interception.
it is helpful to you.
2y= -x+4
y = -1/2x + 2 the slope is -1/2 and the y-intercept is 2.
2x + 4y = 8
4y = -2x + 8
y = -2/4 x +2
y= -1/2 x +2 the slope for this equation is also -1/2 and the
y-intercept is also 2.
If we try to graph these "two" line we quickly see that they are, in fact, the same line, where there is not one point of interception, but rather, all points are common to both.
When graphing the solution to a system of first degree equations like these, there are three possible outcomes. They will intercept at one point (x,y); or, as in this case, they are the same equation and all points are common; or the lines are parallel, they have the same slope but a different y-intercept, and they have no point of interception.
it is helpful to you.
Answered by
2
Heya
_______________________________
x + 2y = 10 ... Equation ( i )
2( x + 2y ) = 8
=>
x + 2y = 4 ... Equation ( ii )
EQUATION i and ii shows that these two lines are // so, there is no solution of the given two EQUATIONs.
_______________________________
x + 2y = 10 ... Equation ( i )
2( x + 2y ) = 8
=>
x + 2y = 4 ... Equation ( ii )
EQUATION i and ii shows that these two lines are // so, there is no solution of the given two EQUATIONs.
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