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Water in a Canal, 30 cm wide and 12 m deep is flowing with a velocity of 20 km per hour. How much area will it irrigate, if 9cm of standing water is desired.
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Given:
Width of the canal = 30 cm = 3 m
Depth of the canal = 12 m.
Given that water is flowing with a velocity of 20 km/hr.
So, the length of the water column formed in (1/2) hour = 10 km = 10000 m.
So, the volume of water flowing in (1/2) hour = (10000 * 3 * 12)
= 360000 m^3.
Let the area to be irrigated in (1/.2) hour be 'x'.
⇒ x * (9/100) = 360000
⇒ x = 36000000/9
⇒ x = 4000000 m^2.
Therefore, the canal irrigated 4000000 m^2 (or) 4 km^2 area in (1/2) hour.
Hope it helps!
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