Question

Hey mate ...
I will mark you as brainliest...

Answer 1 to 4

Answer 1

1)

Ratio 1:√3

Let bar is K

Shadow √3K

K|

|

|

|____________

√3K

Tan@= K/√3K = 1/√3

Tan@= Tan30°

@=30°

Angle of elevation of sun is 30°.

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2)

Chords equidistant from the centre are equal.

So their ratio is 1:1

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3)

AG=6cm

BE=12.6cm

FG=3 cm

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4)

X=65°

Y=115°

Z=89°

In cyclic quadrilateral ABCD

|_ABC +|_ADC= 180°

|_BAD +|_BCD =180°

Angle on point D =180° (straight line)

|_ADC+|_EDC= 180°

|_BCD+|_FCD =180

Again in cyclic quadrilateral CDEF

Similarly

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5)

Let ABCD be the cyclic quadrilateral

with AD parallel to BC. The center of

the circle is O.

since AD is parallel to BC and AC is the transverse

angle DAC = angle ACB

angle DAC is subtended by chord DC on the circumference and angle ACB is subtended by chord AB.

If the angles subtended by 2 chords on the circumference of the circle are equal, then the lengths of the chords is also equal.

Hence,

DC = AB i.e. the 2 remaining sides of the cyclic quadrilateral are equal.

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Now, BD and AC are the 2 diagonals.

In triangle ABD and triangle DCA

AB = CD

|_ DCA = |_DAB (angles subtended by the same chord AD)

|_ ACB = |_ DAC(proved above)

Hence,

triangle ABD is congruent to triangle DCA .

hence, BD = AC