hey mate my next question from you plzz solve it thanx good night sd tc
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As we know opposite angles of cyclic quadrilateral sum is 180
So 4y + 20 - 4x = 180
Also 3y - 5 -7x + 5 = 180
3y - 7x = 180
4y - 4x = 160
y - x= 40
3y - 3x = 120
3y - 7x = 180
subtract
4x = -60
x= -15
y = 40 + x = 25
So angles are 70, 60, 120,110
So 4y + 20 - 4x = 180
Also 3y - 5 -7x + 5 = 180
3y - 7x = 180
4y - 4x = 160
y - x= 40
3y - 3x = 120
3y - 7x = 180
subtract
4x = -60
x= -15
y = 40 + x = 25
So angles are 70, 60, 120,110
himangi48bhatia:
thanx
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here is the answer.........
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