Question

Hey mate please solve this it is urgent. the correct will be marked as brainliest.



And you have to factorise the question given above. ​

Answer 1

Answer:

Please refer to the attachment for your answer!!!

THANK YOU

Answer 2

Question :

Factorize :

$\tt{ {64a}^{3} + {125b}^{3} + {12a}^{2}b + {15ab}^{b}}$

Answer :

If we carefully observe the given problem it is in the form of the expansion of the identity :

$\tt{ {(a+b)}^{3} \implies {a}^{3} + {b}^{3} + {3a}^{2}b + {3ab}^{2}}$

Here :

a => $\tt{ {64a}^{3}}$

It can be written as : $\tt{ a \implies {(4a)}^{3}}$

b => $\tt{ {125b}^{3}}$

It can be written as : $\tt{ b \implies {(5b)}^{3}}$

The expansion of $\tt{ {(a+b)}^{3} is \: {a}^{3} + {b}^{3} + {3a}^{2}b + {3ab}^{2}}$. So , we only need to factorize (a) and (b) to factorize the whole equation.

So factorization :

$\large{\boxed{\tt{ {(4a + 5b)}^{3}}}}$

Here we have taken the power 3 as common.

The factorization can be even expanded as :

(4a + 5b)(4a + 5b)(4a + 5b)