Question

HEY MATE❤❤❤........ Pls HELP....... THERE ARE ZEBRAS AND OSTRICHES IN A ZOO. U COUNT 80 HEADS AND 200 LEGS .THEN FIND THE NO. OF OSTRICHES IN THE ZOO......... PLS DON'T SPAM....​

Answer 1

Answer:

• 80 heads
• 2 leg = ostriche
• 80/2
• = 40

Answer 2

Let the number of zebras be x and Ostriches be y.

(i) Head count is 80.

x + y = 80 {Both have one head}

(ii) Legs Count is 200.

4x + 2y = 200 {Zebra have 4 legs and ostriches have 1 leg}

Now,

On Solving (i) * 2 & (ii), we get

2x + 2y = 160

4x + 2y = 200

----------------------

2x = 40

x = 20.

Substitute x in (ii), we get

4x + 2y = 200

4(20) + 2y = 200

80 + 2y = 200

2y = 120

y = 60.

Therefore:

Number of Zebras = 20

Number of Ostriches = 60

Hope it helps!