Question

hey mate
plz answer fast

1] d [logx] / dx
2] d [e^x lnx} / dx

do differentiation

FASTT

Answer 1

Hey mate

Hey mate

1) We know theorem that

$\frac{d \: log_{x} }{dx } = \frac{1}{x}$

which is final result of first part.

Note:

$lnx = log_{n}(x)$

2) Here we will use following formula

$\frac{d \: uv}{dx} = u \frac{dv}{dx} + v \frac{du}{dx}$

On keeping in mind all theorems of differentiation we get differentiation as follows:

ex/x+lnx.ex

hope it helps