Question

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Answer 1

$\mathfrak{Heya!!}$.

$\mathfrak{Answer}$.

Let the present age of Aftab be 'x'

Let the present age of Daughter be 'y'

A.T.Q

7 years ago, Age of Aftab = x-7

Age of daughter =y-7

Aftab =7 times of Daughter.

(x-7)=7(y-7)

x-7=7y-49

x-7y=-49+7

We got,

X-7y=-42.--------(1)

After 3 years,

Age of Aftab =x+3

Age of daughter =y+3

Aftab =3 times of Daughter

x+3=3(y+3)

x+3=3y+9

x-3y= 9-3

We got,

x-3y=6----------(2)

Now.... Find the solution for both the equations, i.e., (1) and (2).

[Solutions and the graph drawn in the attachment. Please do check it ].

Thanks ✌❤

Answer 2

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