HEY MATE
plz solve this fast
the equation
![sin^{2} x - 2 sinx +a =0 sin^{2} x - 2 sinx +a =0](https://tex.z-dn.net/?f=sin%5E%7B2%7D+x+-+2+sinx+%2Ba+%3D0)
will have at least one real root if
1] a ∈ [ -3,1]
2] a ∈ [-1 ,1]
3] a ∈ [ 0 ,1]
4] none of these
FULL EXPLANATION NEEDED
fast..........
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Step-by-step explanation:
which is required ans.
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