Question

hey mate



solve both the question..............



please​

Answer 1

payhyle Bala Answer 288

Answer 2

3). let's solve it

so, (64)^2/3 => 4^2=> 16


$\sqrt[3]{125} = 5$
3^0 is 1
1/2^-5= 2^5=32

(27)-2/3= 3^-2=1/9
(25/9)^-1/2=(9/25)^2=3/5

now we just have to add them

16+5+1+32x3/5
16+5+1+96/5
(80+25+5+96)/5
206/5

$41 \binom{1}{5}$
here is ur answer mark as brainliest