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Suppose that f(x) is a periodic function with period 1/2 and that f(2)=5, f(9/4)=2, and f(11/8)=3. Evaluate f(1/4)& f(-5)
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f( 9/4) = 2
As period is 1/2
So f( 9/4 - n/2) = 2
Let's check if n is integer for
9/4 - n/2 = 1/4
n/2 = 1/2
n= 1
So here f(1/4) is 2
f(2) = 5
f( 2 - n/2) = 5
let's check for -5
2 - n/2 = -5
n/2 = 7
n= 14
So f(-5) = 5
As period is 1/2
So f( 9/4 - n/2) = 2
Let's check if n is integer for
9/4 - n/2 = 1/4
n/2 = 1/2
n= 1
So here f(1/4) is 2
f(2) = 5
f( 2 - n/2) = 5
let's check for -5
2 - n/2 = -5
n/2 = 7
n= 14
So f(-5) = 5
ZiaAzhar89:
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