Question

Hey Mates !

A rectangular hall is 20m 16cm long and 15m 60 cm broad. Find the maximum size of the square shaped tiles which will completely cover the floor of the hall.

Answer 1

Hope this helps you ☺☺☺

Answer 2

Hey !!

Here's your solution... ⬇⬇

Length of rectangular hall = 20m 16cm
= 2000 + 16 cm --( 1m = 100cm )
= 2016 cm

Breadth of rectangular hall = 15m 60cm
= 1500 + 60 cm
= 1560 cm

Find H.C.F of ( 2016, 1560 )

2016 = 2^5 × 3^2 × 7
1560 = 2^3 × 3 × 5 × 13

H.C.F = 2^3 × 3
= 24
Maximum size of the square shaped tiles which will completely cover the floor of the hall is 24cm.

Number of tiles required to cover floor =
$= \frac{area \: \: of \: \: rectangular \: \: hall}{area \: \: of \: \: square \: \: shaped \: \: tile} \\ \\ = \frac{2016 \times 1560}{ {(24)}^{2} } \\ \\ = 5460$
5460 tiles of square shaped ( 24cm ) are required to cover the rectangular hall.

HOPE IT HELPS..

THANKS ^-^