Question

⚡⚡⚡HEY MATES⚡⚡⚡⚡⚡⚡⚡⚡⚡⚡⚡

AIEEE 2012

ATOMIC STRUCTURE

Awesome question for u all

Answer 1

1) n=4 l=1 =>4p orbital

2)n=4 l=0=> 4s orbital

3) n=3 l=2=> 3p orbital

4) n=3 l=1=>3d orbital

then, according to Afbau principle energies of above mentiond orbitals


4p> 3d> 4s> 3p

Answer 2

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▶ Explanation :-



According to Afbass rule :-


n = n + l


1) Given : n = 4 and l = 1


n = 4 + 1


n = 5


∴ The shell can be 4p


2) Given : n = 4 and l = 0



n = 4 + 0


n = 4


∴ The shell can be 4s


3) Given : n = 3 and l = 2


n = 3 + 2


n = 5


∴ The shell can be 3d


4) Given : n = 3 and l = 1


n = 3 + 1


n = 4


∴ The shell can be 3p



In the above cases, we can observe that 4p and 3d have the same value, but 4p have the higher energy because in the periodic table 4p comes after 3d


4s and 3p have same value, but 4s comes after 3p. So 4s have the higher energy.


∴ Increasing order of the energy = ( 4 ) < ( 2 ) < ( 3 ) < ( 1 )


∴ Option ( b ) is correct




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