Question

HEY MATES!!!!! answer to the above question!!!! In the first it is not PS it is PQ.​

Answer 1

answer is 10 correct hai

Answer 2

Heya!!

in right angled ∆ ORF

R² = x² + y² ..... ( i )

In right angled ∆ OFB

R² = x² + ( 24 - y )²

R² = x² + 576 + y² -48y ....( ii )

4rm i and ii

y = 576/48

y = 12

in right angled ∆ OGD

R² = ( 17 - x )² + z²......(iii)

in right angled ∆ OGC

R² = ( 17 - x )² + ( z - 10 )² ....(iv)

4rm iii and iv

z = 5

R² = x² + 289 - 34x + 25

x² + y² = x² + 289 - 34x + 25

144 = 314 - 34x

34x = 170

x = 5

So,

R² = 25 + 144

R = √169

R = ±13

R = -13 ( rejects )

So, R = 13cm