Question

hey mates
can anyone pls help ....it's my exm today

derivation of velocity time graph

plss help....


​

Answer 1

Answer:

Consider a particle moving along a straight line with uniform acceleration 'a'. At t = 0, let the particle be at A and u be its initial velocity and when t = t, v be its final velocity.

v = u + at I equation of motion

Graphical Derivation of First Equation of Motion

Consider an object moving with a uniform velocity u in a straight line. Let it be given a uniform acceleration a at time t = 0 when its initial velocity is u. As a result of the acceleration, its velocity increases to v (final velocity) in time t and S is the distance covered by the object in time t.

The figure shows the velocity-time graph of the motion of the object.

Slope of the v - t graph gives the acceleration of the moving object.

Thus, acceleration = slope = AB =

v - u = at

v = u + at I equation of motion

Answer 2

Answer:

hii prerna your status soo good and god bless you that you become english lecturer