hey mates,,,
can u solve it for me:
If for an AP the first term is 3 and the common difference is 6 then find Sn and hence find S10
Answers
Answered by
3
Step-by-step explanation:
this is your answer.. 300 and 3n^2
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Answered by
4
Step-by-step explanation:
a=3
d=6
Sn = n /2 [2a + (n-1)d]
= n/2 [2 x 3 + (n-1) 6]
= n/2 [6 + 6n - 6]
= n/2 [6n]
= n/2 x 6 (n)
= n x 3n
= 3n^2
S10 = n/2 [2a + (n-1)d]
= 10/2 [2 x 3 + (10-1)6]
= 5 [6 + 9x 6]
= 5 (6+54)
= 5 (60)
= 300
Hope this helps you buddy! Mark this as the brainlist answer!
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