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Q. Find an anti derivative of the function (ax+b)^ 2 by the method of inspection.
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hello
We know that ddx(ax+b)3=3a(ax+b)2
⇒(ax+b)2=13addx(ax+b)3.
=ddx[13a(ax+b)3].
Hence 13a(ax+b)3 is an anti derivative of (ax+b)2.
hope it helps !!
SurbhiAmbashta:
are u in 12th?
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