hey mates hope u all have tomorrow a happy Sunday here is my new question Plzz ans. if u know thanx for giving ur precious time
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Given : sec θ + tan θ = 7 ---- (1)
We know that sec^2 θ - tan^2 θ = 1
⇒ (sec θ + tan θ)(sec θ - tan θ) = 1
⇒ (7)(sec θ - tan θ) = 1
⇒ sec θ - tan θ = 1/7.
On solving (1) & (2), we get
⇒ sec θ + tan θ = 7
⇒ sec θ - tan θ = 1/7
-------------------------
2 sec θ = 50/7
sec θ = 50/14.
Therefore, the value of sec θ = 50/14 (or) 25/7.
Hope it helps!
himangi48bhatia:
thanxxxxx
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