Question

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Explain Gay Lussacs Law in detail....

Answer 1

Gay Lussacs Law Gay-Lussac's law. Gay-Lussac's lawcan refer to several discoveries made by French chemist Joseph Louis Gay-Lussac (1778–1850) and other scientists in the late 18th and early 19th centuries pertaining to thermal expansion of gasses and the relationship between temperature, volume, and pressure.
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source -: WIKIPEDIA

Answer 2

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Gay Lussac’s law defines the relationship between the pressure and temperature of a gas. According to the law, when volume is held constant, the pressure of an ideal gas is directly proportional to its temperature. This law can be expressed as follows:

 



 

Where, P1 and P2 are the Initial Pressure and Final Pressure respectively. Both the pressures are in the units of atm. T1 refers to the Initial Temperature and T2 refers to the Final Temperature. The temperatures are measured in the units of Kelvin.

This can be explained as, at constant volume of a close container, if the pressure inside container increases, the temperature inside the container also increases. Pressure vs. Temperature graph is linear for ideal gases.

Derivation:

According to the Gay Lussac’s Law, at constant volume, the pressure of a fixed mass of a gas is directly proportional to its absolute temperature.
Since P and T vary directly, we can equate them by making use of a constant k.


The value of k depends on the pressure of the gas, its amount and also on the unit of volume V.

----------- (2)

If the temperature is changed to a new value, let’s say T2, and then the pressure will change to P2. Then we get,
 ----------- (3)

Equating (2) and (3), we get

In general, we can write it as
Or
P1T2=P2 T1