Question

Hey mates!!

If Sec A + tan A = p

What is the value of---

sec A - tan A?


Thanks!

Answer 1

Hey mate!

Here is your answer....


Given,

Sec A + tan A = 1

sec A - tan A = ?


As we know,

sec²A - tan²A = 1

(sec A+tan A) (sec A-tan A) = 1

p(sec A-tan A) = 1

sec A - tan A = 1/p


Therefore,

sec A - tan A = 1/p


Hope it helps u bro... :)

Answer 2

☇Given secA + tan A = p

☇Recall the identity, sec2A – tan2A = 1

⇒ (secA + tan A)(secA – tanA) = 1

⇒ p × (secA – tanA) = 1 ∴ (secA – tanA) = 1/p

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