Question

Hey mates!

If tan A = cot B and A, B are acute angles.... Prove that,

A+B = 90°


Thanks!

Answer 1

Hey dear!

Yr answer is here....

Given that,

tan A = cot B

Now,

tan A = cot B

[ cot (90-Φ) = tan Φ]

[ tan (90-Φ) = cot Φ]

cot(90-A) = cot B

cot B = cot(90-A)

by cancelling cot,

B = 90-A

A+B = 90°

Hence Proved!!

Hope it helps u...

Answer 2

Hey !!

Thanks for the question.

Given,

Tan A = Cot B

Tan A = Tan ( 90 - B )( According to identity formula )

A = 90 - B

A + B = 90

Hence , proved.