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Answered by
213
Q 6. Solution :-
Calculating the C.F :-
◘ 10 + x + y = 20
⇒ x + y = 20 - 10
⇒ x + y = 10 . . . (i)
◘ Median = 14.4
So, Median class is 12 - 18
Now,
- Lower limit of the Median Class, l = 12
- Class width, h = 6
- Cumulative frequency of the class before the Median Class, cf = 4 + x
- n/2 = 20/2 = 10
- Frequency of the Median Class, f = 5
We know,
Putting the value of x in eq. (i) :-
Anonymous:
Great !
Answered by
246
Given :
- The median of the distribution is 14.4
- Total frequency is 20.
To Find :
- Find the value of x and y.
Solution:
Median = 14.4....(given)
So, Median class = 12-18
- Lower limit of median class (l) = 12
- Class interval (h) = 6
- CF = 4 + x
- Frequency of the median class = 5
- n/2 = 20/2 = 10
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Now,
➨10 + x + y = 20
➨x + y = 10
➨y = 10 - 4.....(putting x = 4)
➨
Therefore, value of x and y are 4 and 6 respectively.
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