Question

Hey mates......
please help me in these questions....
don't tell direct answer.....
Tell all of these please​

Answer 1

Answer:

Step 1 recall the nearest number whose square would me near to it

step2 then divide it by that number

step 3 then subtract or add the bumber

Answer 2

Step-by-step explanation:

{1}

(1)^2 = 1

(9)^2 = 81 ( √any no unit digit 1 = unit digit 1or 9)

(2)^2 = 4

(8)^2 =64(so √any number unit digit 4= unit digit is always 2 or 8

(3)^2= 9

(7)^2= 49 ( so √any number unit digit 9 = unit digits 3 or 7 )

(4)^2 = 16

(6)^2 = 36 ( √any no unit digit 6 = unit digits 4 or 6

(5)^2 = 25 ( √any no unit digit 5 = unit digit 5 )

now solutions

(a) unit digit √9604= take √4 = so unit digits are 2 or 8

(b) √99225 = 5

(c) √996004 = 2 or 8

(d) √1525225 = 5

(e) √106276 = 4 or 6

{2}

(a) 576 = 2×2×2×2×2×2×3×3

make pair (2×2)×(2×2)×(2×2)×(3×3)

take one number from every pair 2×2×2×3 = 24

√576= 24

similarly solver all problems

{3}

(a) 392

prime factors of 392

392 = 2×2×2×7×7

make pairs (2×2)×(7×7)×(2)

here we need one more 2 for complete pair therefore we multiply by 2 so we get perfect square number

ans = 2

similarly solve all questions

{4}

(a) 4050

prime factors of 4050

4050 = 2×3×3×3×3×5×5

make pairs

4050= (3×3)×(3×3)×(5×5)×(2)

if we remove 2 from factors then pair will be complete ..for removing 2 we need to divide 4050 by 2

ans = 2

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