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A car changes its speed from 20km/h to 50km/h of mass 3600kg in 5s. Determine the net external force applied on the car is
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Answer:
NET EXTERNAL FORCE ( F ) = 6000 NEWTON
Explanation:
★ NEWTON'S LAWS OF MOTION ★
★ GIVEN ;
» Initial Velocity ( U ) = 20 km / h
[ 20 km / h = 20 × 5 / 18 = 50 / 9 (m / sec.) ]
» Final Velocity ( V ) = 50 km / h
[ 50 km / h = 50 × 5 / 18 = 125 / 9 (m / sec.) ]
» Mass of Car ( m ) = 3600 kg
» Change in Time ( ∆ t ) = 5 seconds
★ NET EXTERNAL FORCE ( F ) = ???
_______ [ BY USING FORMULA ] _______
]
★ Force = ∆ p / ∆ t
= mv - mu / ∆ t
= m ( v - u ) / ∆ t
= 3600 [ ( 125 / 9 ) - ( 50 / 9 ) ] / ∆ t
= 3600 [ 75 / 9 ] / ∆ t
= 400 [ 75 ] / 5
= 400 [ 15 ]
= 6000 N
_________________________________
★ FORCE ( F ) = 6000 NEWTON
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