Question

❤▄▄Hey mates▄▄❤
Please slove this question stepwise.☺
​

Answer 1

Answer:

$\boxed { \displaystyle \rm \Green{Answer}}$

ᴀᴘᴘʟʏ ᴛʜᴇ ғᴏʀᴍᴜʟᴀ ᴘᴠ=ɴʀᴛ

ᴠᴏʟᴜᴍᴇ ᴏғ ɢᴀs ᴀ = ᴠᴀ = ɴᴀʀᴛᴀ/ᴘᴀ

ᴠᴏʟᴜᴍᴇ ᴏғ ᴅɪʜʏᴅʀᴏɢᴇɴ = ᴠ = ɴʀᴛ/ᴘ

sɪɴᴄᴇ ᴠᴀ = ᴠ

ɴᴀʀᴛᴀ/ᴘᴀ = ɴʀᴛ/ᴘ

ᴘ=ᴘᴀ sᴏ ɪᴛ ᴡɪʟʟ ᴄᴀɴᴄᴇʟ ᴏᴜᴛ.

ʀ ᴡɪʟʟ ᴀʟsᴏ ʙᴇ ᴄᴀɴᴄᴇʟʟᴇᴅ ғʀᴏᴍ ʙᴏᴛʜ sɪᴅᴇ.

ɴᴀ = ɴᴛ/ᴛᴀ

ᴘᴜᴛᴛɪɴɢ ᴛʜᴇ ᴠᴀʟᴜᴇs ɪɴ ғᴏʀᴍᴜʟᴀ :

ɴ= 0.184/2

ᴛ= 17+273 = 290ᴋ

ᴛᴀ = 95 + 273 =368

ɴᴀ= 0.184/2 * 290/368 = 0.0725

ɴᴀ= ɢɪᴠᴇɴ ᴍᴀss ᴏғ ɢᴀs / ᴍᴏʟᴀʀ ᴍᴀss ᴏғ ɢᴀs

0.0725 = 2.9 /ᴍᴏʟᴀʀ ᴍᴀss ᴏғ ɢᴀs

ᴍᴏʟᴀʀ ᴍᴀss ᴏғ ɢᴀs = 2.9/0.0725 = 40ɢ

Explanation:

Follow me

mark as brainliest✨

physics expert✌

Answer 2

Let mass of unknown gas is = m

M(g) = 5.40 gm

T(g) = 27℃ = (273 + 27)K = 300K

V(g) = V(H) = V

P(g) = P(H) = P

M(H) = 0.14 gm

T(H) = 17℃ = (17+273)K = 290K

• Here, 'g' refers to the unknown gas
• and, 'H' refers to the Hydrogen Gas.

Now, For the unknown gas:

P(g)×V(g) = n×R×T(g)

=> PV = M(g)/m × RT(g) ................(i)

For Hydrogen gas:

P(H)×V(H) = n×R×T(H)

=> PV = M(H)/1 × RT(H) ..................(ii)

Since LHS of (i) and (ii) are equal, there hence, their RHS must also be equal.

That is,

M(g)/m ×RT(g) = M(H) ×RT(H)

=> M(g)/m × T(g) = M(H) × T(H)

=> 5.4/m × 300 = 0.14 × 290

=> (5.4×300)/m = (290×0.14)

=> 1620/m = 40.6

=> m = 1620/40.6

= 39.901 gm

≈ 40 gm

Hence, molecular mass of the unknown gas is 40gm.