Question

Hey mates!! Please solve this one!!! And explain properly and easily.......
Ques. =>Find the probability that a non leap year selected at random will contain 53 sundays.
{Hint=> in a leap year, there are 52 sundays and 1 extra day}

Answer 1

a leap year contain 52 Sundays so it is not possible to have 53 Sundays in a non leap year.

no. of events n(e)=0
no. of outcomes n(o)= if we take infinity (20XX to XXXX or more)

so probability=n(e)/n(o)

Ans: the probability is 0.