Hey mates!! Please solve this one!!! And explain properly and easily.......
Ques. =>Find the probability that a non leap year selected at random will contain 53 sundays.
{Hint=> in a leap year, there are 52 sundays and 1 extra day}
Nishit2312:
Answer is 2/7
There r 2 extra days..so acc to sample space,the probability comes out to be 2/7..
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a leap year contain 52 Sundays so it is not possible to have 53 Sundays in a non leap year.
no. of events n(e)=0
no. of outcomes n(o)= if we take infinity (20XX to XXXX or more)
so probability=n(e)/n(o)
Ans: the probability is 0.
no. of events n(e)=0
no. of outcomes n(o)= if we take infinity (20XX to XXXX or more)
so probability=n(e)/n(o)
Ans: the probability is 0.
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