Question

Hey mates pls answer this questions class 9 force and laws of motion pls answer only if you know

Answer 1

Answer:

Hi your answer is as follows

Explanation:

M = 4 kg            

m  = 50 g

v  = 35 m/sec

initial momentum of rifle and bullet together = 0.  So  as per the conservation of linear momentum,

0 = M * (-V) +  m  v

0   = 4 * (-V) + 50/1000  * 35

V =  0.4375  m/sec    recoil velocity

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Mass of first objects, m₁= 100 g = 0.1 kg  

Mass of second object, m₂ = 200 g = 0.2 kg  

Velocity of m₁ before collision, v₁= 2 m/s  

Velocity of m₂ before collision, v₂ = 1 m/s  

Velocity of m₁ after collision, v₃ = 1.67 m/s  

Velocity of m₂ after collision = v₄

According to the law of conservation of momentum:  

Total momentum before collision = Total momentum after collision  

m₁v₁ + m₂v₂ = m₁v₃+ m₂v₄

⇒ 0.1 * 2 + 0.2 * 1 = 0.1 * 1.67 + 0.2 * v₄  

⇒ 0.4 = 0.67 + 0.2 * v₄  

⇒ v₄  = 1.165 m/s  

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