hey mates.. pls answer with reason ??
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bulb a will fuse because it given more charge
anshuman43:
pls explain more deatilly friend
Hey are u in 10th
hmm
hey pls explain.. detaillly by editing your answer
I am 8th class
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I’m in 10th too so don’t expect this to be perfect. But,
Current(I)=V^2/P
In Bulb A,
V-220V
P-50W
Therefore, I=220*220/50
I=968 A
In Bulb B,
V-220V
P-100W
Therefore, I=220*220/100
I=474 A
Since, A utilises a higher amount of current, for safety purposes A will be the bulb which gets the fuse.
Current(I)=V^2/P
In Bulb A,
V-220V
P-50W
Therefore, I=220*220/50
I=968 A
In Bulb B,
V-220V
P-100W
Therefore, I=220*220/100
I=474 A
Since, A utilises a higher amount of current, for safety purposes A will be the bulb which gets the fuse.
I’m pretty sure it’s right. However, please feel free to correct me.
But R=V^2/P
I= P/V
can we apply this formula
see we use P = V^2 / R only in parallel combination not in series
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