Question

Hey mates ....
Pls help me with this question..
In the fig . 6.17 .
POQ is a line . Ray OR is perpendicular to line PQ . OS is another ray lying between rays OP and OR . Prove that
ANGLE ROS = 1/2 ( ANGLE QOS - ANGLE POS )

The best answer will be marked brainliest​

Answer 1

Step-by-step explanation:

In angle ROP ,ROS = ROP - SOP -- (1) In angle SOQ , ROS = SOQ - ROQ - (2) From (1) and (2) 2(ROS) = (QOS - POS)

Answer 2

, please

mark me as brainlist