Question

hey mates!!
plz solve this for me..
the best ans will be marked as brainliest♥♥ ​

Answer 1

$\bf{\huge{\underline{\boxed{\rm{\blue{Answer:}}}}}}$

Given:-

• The sum of digits of two numbers is 12
• When 18 is added to it, the digits are reversed.

To find :-

• The number formed.

Solution :-

Let the digit in the units place be x

Let the digit in the tens place be y

•°• Original Number = 10y + x

As per the first condition,

• the sum of the digits = 12

x + y = 12 -----> 1

As per the second condition,

• When 18 is added the digits are reversed.

Reversed number = 10x + y

18 is added,

10y + x + 18 = 10x + y

Transporting the terms,

10y - y + 18 = 10x - x

9y + 18 = 9x

9x = 9y + 18

9x - 9y = 18

Figure out the common,

9 ( x -y) = 18

x - y = $\bf\large\frac{18}{9}$

x - y = 2 ----->2

Add equation 1 to 2 and solve them simultaneously by elimination method,

..... x + y = 12 ------>1

..... x - y = 2 -------> 2

-------------------

.....2x = 14

x = $\bf\large\frac{14}{2}$

$\bf{\large{\boxed{\rm{\blue{ <strong><u>x</u></strong><strong><u> </u></strong><strong><u>=</u></strong><strong><u> </u></strong><strong><u>7</u></strong>}}}}}$

Put the value of x in equation 1

x + y = 12

7 + y = 12

y = 12 - 7

$\bf{\large{\boxed{\rm{\green{ <strong><u>y </u></strong><strong><u>=</u></strong><strong><u> </u></strong><strong><u>5</u></strong>}}}}}$

$\bf{\large{\underline{\boxed{\rm{\pink{Solution :\: (x, y) = (7,5)}}}}}}$

Substitute the value of x and y in the original number, 10y + x

=> 10 × 5 + 7

=> 50 + 7

=> 57.

$\bf{\large{\boxed{\underline{\rm{\red{Number\: = 57}}}}}}$