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Prove that angle of incidence is equal to the angle of emergence.
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The angle of emergence is equal to the angle of incidence. ... In case of a prism, the normal at the point ofincidence is not parallel to the normal at the point of emergence. Therefore, in a prism, the angle of emergence is not, in general, equal to the angle of incidence.
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Assume ABCD to be the glass plate with sides AB parallel to CD.
Let the refractive index of air and glass be n1and n2.
Consider a ray of light EF incident on surface AB of the glass slab with angle of incidence, ∠i.
The light ray is refracted into the glass slab along the path FG and towards the normal, NN’ . ∠ r1 is the angle of refraction.
The light ray is refracted out of the glass slab at the surface CD along the path GH. The angle of incidence at this surface is ∠r2.
The light ray emerges out of the slab forming ∠e as angle of emergence.
The surfaces AB and CD are parallel and FG is the transversal,
Therefore, ∠r1= ∠r1
Let the refractive index of air and glass be n1and n2.
Consider a ray of light EF incident on surface AB of the glass slab with angle of incidence, ∠i.
The light ray is refracted into the glass slab along the path FG and towards the normal, NN’ . ∠ r1 is the angle of refraction.
The light ray is refracted out of the glass slab at the surface CD along the path GH. The angle of incidence at this surface is ∠r2.
The light ray emerges out of the slab forming ∠e as angle of emergence.
The surfaces AB and CD are parallel and FG is the transversal,
Therefore, ∠r1= ∠r1
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