hey mates solve it fast wit all the steps..please
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Formula is
the sum of square of perpendicular and base is equal to square of hypoteneous
so, (pq)^2+(qr)^2= (pr)^2
3^2+qr^2=6^2
9+qr^2=36
qr^2=36-9
qr^2=25
qr=√25=5 ans
the sum of square of perpendicular and base is equal to square of hypoteneous
so, (pq)^2+(qr)^2= (pr)^2
3^2+qr^2=6^2
9+qr^2=36
qr^2=36-9
qr^2=25
qr=√25=5 ans
sahilyallur:
i need the angles qpr and prq
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