Question

hey mates !



Two black kings and two black jacks are removed from a pack of 52 cards.

Find the probability of getting:

a) a card of clubs
b) a king
c) a black card
d) a red king

d) either a red card or a king
e) neither an ace nor a king

f) a jack,queen or a king




please help me ​

Answer 1

Answer:

a) 11/48

b) 1/24

c) 11/24

d) 1/24

d) 13/24

e) 11/12

f) 1/6

Step-by-step explanation:

a) S= {48 cards}

A = {11 black cards}

n(A) = 11

p(A) = 11/48

b) B = {2 kings}

n(B) = 2

p(B) = 2/48

= 1/24

c) C = {22 black cards}

n(C) = 22

p(C) = 22/48

= 11/24...

I stop here...as said by u

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Answer 2

hello....

hope this picture help u