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What's the last digit of 7^500
MonsieurBrainly:
wrong
Answers
Answered by
13
Answer:
1
Step-by-step explanation:
Cyclic chart of 7 is:
7¹ = 7
7² = 49
7³ = 343
7⁴ = 2401
7⁵ = 16807
7⁶ = 117649.
From the above it is clear that cyclicity of 7 is 4. Now, with the cyclicity number i.e 4 divide the given number i.e 500. The remainder obtained is 0.
Thus, the last digit of 7⁵⁰⁰ is equal to the last digit of 7⁰ i.e 1.
Therefore, last digit of 7⁵⁰⁰ = 1.
Hope it helps!
Answered by
6
Solution :-
7^4 ≡ 1 ( mod 100 )
⇒ 500 = 125 × 4
7^500 ≡ 7^125 × 4 ( mod 100 )
7^500 ≡ (7^4)^125 ( mod 100 )
7^500 ≡ (1)^125 ( mod 100 )
7^500 ≡ 1 ( mod 100 )
∴ The last digit of 7^500 = 1
7^4 ≡ 1 ( mod 100 )
⇒ 500 = 125 × 4
7^500 ≡ 7^125 × 4 ( mod 100 )
7^500 ≡ (7^4)^125 ( mod 100 )
7^500 ≡ (1)^125 ( mod 100 )
7^500 ≡ 1 ( mod 100 )
∴ The last digit of 7^500 = 1
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