Math, asked by Anonymous, 1 year ago

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What's the last digit of 7^500


MonsieurBrainly: wrong

Answers

Answered by siddhartharao77
13

Answer:

1

Step-by-step explanation:

Cyclic chart of 7 is:

7¹ = 7

7² = 49

7³ = 343

7⁴ = 2401

7⁵ = 16807

7⁶ = 117649.


From the above it is clear that cyclicity of 7 is 4. Now, with the cyclicity number i.e 4 divide the given number i.e 500. The remainder obtained is 0.

Thus, the last digit of 7⁵⁰⁰ is equal to the last digit of 7⁰ i.e 1.


Therefore, last digit of 7⁵⁰⁰ = 1.


Hope it helps!


siddhartharao77: Thank you :-)
Answered by BIGBANG1234
6
Solution :-


7^4 ≡ 1 ( mod 100 )


⇒ 500 = 125 × 4


7^500 ≡ 7^125 × 4 ( mod 100 )


7^500 ≡ (7^4)^125 ( mod 100 )


7^500 ≡ (1)^125 ( mod 100 )


7^500 ≡ 1 ( mod 100 )


∴ The last digit of 7^500 = 1





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