Question

HEY MATHEMATICIANS I got a task for you
find the value of y using the above pic.​

Answer 1

Answer:

Step-by-step explanation:

$\frac{y}{0} = \frac{1}{a^{2}-b^{2} }$

By using cross multiplication method.

y * $(a^{2} - b^{2})$ = 1 * 0

y *{(a+b) (a-b)} = 0

y(a+b)*y(a-b)

(ya + yb) * (ya - yb) = 0

ya + yb = $\frac{0}{ya-yb}$

ya =  $\frac{0}{ya-yb}$ - yb

ya = $\frac{0}{ya-yb} - \frac{yb}{1}$

ya = $\frac{0}{ya-yb} - \frac{yb * ( ya - yb)}{ya - yb}$

ya = $\frac{-(yb * ( ya - yb))}{ya - yb}$

ya = $\frac{-[yb * (y( a - b))]}{y(a - b)}\\ya = -yb\\a= -b$

put the value of a in the eqation.

$\frac{y}{0} = \frac{1}{a^{2} - b^{2} }\\\frac{y}{0} = \frac{1}{-b^{2} - b^{2} } \\\frac{y}{0} = \frac{1}{-2b^{2} }$

by cross multiplication

$y*(-2b)^{2} = 0\\y = \frac{0}{-2b^{2} } \\y = 0$

Hope it helps.

Mark brainliest.

Answer 2

Answer:

y: 0

please mark as brainliest