Question

hey mere ques ka ans dedo plzzz the work function for a certain metal is 4.2 eV . will this metal give photoelectric emission for incident radiations of wavelength 330 nm . plzz as a friend ​

Answer 1

No

Work function of the metal,

Charge on an electron, e = 1.6 × 10−19 C

Planck’s constant, h = 6.626 × 10−34 Js

Wavelength of the incident radiation, λ = 330 nm = 330 × 10−9 m

Speed of light, c = 3 × 108 m/s

The energy of the incident photon is given as:

It can be observed that the energy of the incident radiation is less than the work function of the metal. Hence, no photoelectric emission will take place.

Answer 2

According to the question,

$Φ_{0} = 4.2eV$

$ν_{0}h = 4.2$

$ν_{0} = 1.01 \times 10^{15} Hz$

$\bold{Now,}$

Incident wavelength,

$ν = 330\:nm$

$ν = 6 \times 10 ^{ - 19} Hz$

Since,

$ν$ is less than $ν_{0}$, there will be no photoelectric emission.