Question

✨Hey people!✨




Here is my question:-


An atom $X$ has three electrons more than the noble gas configuration. What type of ion will it form? Write the formula of its:-

(a)Sulphate

(b)nitrate

(c)phosphate

(d)carbonate

(e)hydroxide


Thanks!✌❤

Answer 1

X has three electrons more than noble gas configuration 

so,it will form X3-         

formula with sulphate is X₂(SO4)₃
nitrate  is X(NO3)₃
phosphate is XPO4
Carbonate is X₂(CO3)₃
hydroxide is  X(OH)₃

hope this answer helps you

Answer 2

${Answer :-}$

The atom X has there electrons more than a noble gas.

${Note :-}$ An atom always tends to acquire the configuration of its nearest noble gas.

Thus, the atom will lose 3 electrons and so it will form a positive ion.
So, it's ion form is ${ X3+}$

Now, we can conclude that the valency of the element is 3.
Thus,.

(a) Sulphate -

Sulphate is SO4 and its valency is 2.
X atom's valency is 3.

Thus, the form of its Sulphate is X2(SO4)3.

(b) Nitrate

Nitrate is NO3 and its valency is 1.
X atom's valency is 3.

Thus, its Nitrate form is X(NO3)3.

(c)Phosphate

Phosphate is PO4 and its valency is 3.
X atom's valency is 3.

Thus, its Phosphate form is XPO4.

(d) Carbonate

Carbonate is C03 and its valency is 2.
X atom's valency is 3.

Thus, its Carbonate form is X2(CO3)3.

(e)Hydroxide

Hydroxide is OH and it's valency is 1.
X atom's valency is 3.

Thus, its Hydroxide is X(OH)3.

${Note :-}$

The form of a chemical compound is written by interchanging the valency of its components. Refer to the answer, u will understand.

Hope this helps,.

If helps, please mark it as brainliest ^_^