Question

HEY PHYSICS LOVERS, <br />SOLVE IT FAST. <br />The electrostatic force between two charges located 8 metre apart is 0. 10 newton. What will be the force between them when they are located 2 metre apart? <br />(a) 0. 01 N <br />(b) 0. 03 N<br />(c) 0. 8 N<br />(d) 1. 6 N<br /><br />SHOW FULL SOME WITH LOGIC AND PROPER EXPLANATION. <br />NO SPAM. <br />THANK YOU.

Answer 1

Hola User________

Here is Your Answer....!!!!
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⭐Actually welcome to the concept of the ELECTROSTATICS ...

⭐Basically after solving we get this

⭐We get 1.6 N as answer⭐

⭐From first equation we get the relation about the Charges

⭐When we substitute the relation .

⭐we get the Magnitude of the Force for the distance of 2 m apart
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Hope it helps u....☺

Answer 2

Here is your solution

Given that :-

The electrostatic force between two charges located 8 m(radius) apart is 0.10 newton.

We have to find force between them when they are located 2 metre apart?

Now

We know that

$f1 = \frac{k \times q1 \times q2}{r {}^{2} } \\ 0.10 = \frac{k \times q1 \times q2}{8 {}^{2} } \\ \\ kq1 q2 = 0.10\times 64 ......(1)$

From equation first we put value of kq1q2.

$f2 = \frac{k \times q1 \times q2}{r {}^{2} } \\ f2 = \frac{kq1q2}{2 {}^{2} } \\ f2 = \frac{0.10 \times \cancel(64) {}^ \: {16} }{\cancel4} \\ f2 = 1.6 \: newton$

Hence
The force between them when they are located 2 metre apart is 1.6 newton.

Hope it helps you