Question

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Not considering the electronic spin,the degeneracy of the second excited state of H is 9
What is the degeneracy of the second excited state of H negative
[JEE ADVANCED 2015]

Answer 1

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Not considering the electronic spin if the degeneracy of H atom in 2nd excited state is 9 then what is the degeneracy of H^-1 in second excited state?

Answer

2122

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4 ANSWERS

Abhilasha Choudhary, B.tech Materials Science and Engineering & Metallurgy and Materials Engineering, Punjab Engineering College...

Answered May 2, 2016

JEE ADVANCED 2015; a fairly good question that checks the concepts!

Single electron species don't follow the [ n+l ]rule. [(n+l) rule is the rule to find the energy order of the subshells], thus hydrogen being a single electron specie has all its subshells of equal energy in n=3. thus degeneracy( number of orbitals of equal energy for the electron to be excited in ) is 9 {1 s orbital+3p orbitals +5d orbitals}

however hydride ion has a configuration of 1s(2)

FIRST EXCITED STATE: 1s(1) 2s(1)

SECOND EXCITED STATE:1s(1) 2s(0) 2p(1)

we excite the electron form s subshell to p subshell .but yeah..we have 3 p orbitals of equal energy for the electron to be put in !

and this solves the problem ..the answer is 3