Question

Hey please answer this circle Question

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Answer 1

Answer:

(B) x^2 + y^2 - 2x - 2y -7 =0

Explanation:

Circle Eq'n : (x-h)^2 + (y-k)^2 = r^2

r = 3u

centre : (h,k) : solution of given lines

2h + 3k = 5 & 2h - k = 1

upon solving, we get,

h= 1 & k = 1

hence circle Eq'n becomes,

(x-1)^2 + (y-1)^2 = 3^2

x^2 + y^2 - 2x - 2y -7 =0

Answer 2

Explanation:

Centre = (1,1)

9 = (x-1)^2 + (y-1)^2

x^2 +y^2 -2x -2y -7 =0