Question

Hey please anyone help this question from Polynomials?

Answer 1

Hey there !!!!!

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If α and β are roots of quadratic polynomial P(x)

Then P(x) can be represented as x²-(α+β)x+αβ=0

Now,

               x²-(k+6)x+2(2k-1)=0

Comparing  x²-(k+6)x+2(2k-1)=0 with x²-(α+β)x+αβ=0

  α+β=k+6  αβ=2(2k-1)

   α+β=αβ/2

   k+6 =2*(2k-1)/2

  k+6 =2k-1


  6+1 =2k-k


  k=7

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Hope this helped you..............

Answer 2

#CarryOnLearning....