Math, asked by ssajitha063, 11 months ago

hey please give me the best answer of the question​

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Answered by BrainlyMoon
1

Rationalize the following term

6 \sqrt{3}  \times  \frac{6 \sqrt{3} }{6 \sqrt{3} }

 \frac{36 \times 6}{6 \sqrt{3} }

 \frac{36}{ \sqrt{3} }

since the term is in the form of

 \frac{p}{q}

which makes it rational

hence proved

Answered by mrrocker1
0

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If possible let us assume that 6√3 is an rational. no. So it can be written in the form p / q where p and q are coprime integers and q not equals to 0.

6√3 = p / q

√3 = p / 6q

Now √3 is irrational no. and p / 6q is rational. So, √3 can't be equal to p / 6q.

This happened because of our wrong assumption of 6√3 to be rational.

Hence, 6√3 is irrational.

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