Question

Hey please give me the correct answer

Find the value of ♪♪ ⁿnⁿ ♪♪
${9}^{n + 1} \: - \: 2 \: \times \: {9}^{n \: } = 7$

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Answer 1

Answer:

this is the method for this question

Answer 2

Question :

$\sf\odot \:{9}^{n + 1} \: - \: 2 \: \times \: {9}^{n \: } = 7$

Solution :

$\sf{9}^{n + 1} \: - \: 2 \: \times \: {9}^{n \: } = 7$

$\sf \mapsto {9}^{(n + 1)} \times {9}^{n} = 7 + 2$

$\mapsto \sf 9^{(n + 1) + n} = 9$

9 can be written as 9¹ as 9¹ means 9

$\sf \mapsto {9}^{2n + 1} = {9}^{1}$

As the bases are same so they will be excluded

$\sf \mapsto2n + 1 = 1$

Transposing 1 to the other side we get

$\sf \mapsto2n = 1 - 1$

$\sf \mapsto2n = 0$

$\sf \mapsto n = \frac{0}{2}$

$\sf \mapsto n = 0$

Hence, the answer is 0

Additional Information :

$\sf {a}^{m} \times {a}^{n} = {a}^{m + n}$

$\sf \frac{{a}^{m} }{ {a}^{n} } = {a}^{m - n}$