Question

Hey! please help me solve this

Answer 1

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Hi Sis.....
This is AbhijithPrakash....
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The answer for your question is as followed:
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(i) CE = AD [Opposite sides of a Parallelogram]
AD = BC [Given]
∴, BC = CE
⇒∠CBE = ∠CEB
also, 
∠A + ∠CBE = 180° [Angels on \the same side of transversal and ∠CBE = ∠ CEB]
∠B + ∠CBE = 180° [Linear pair]
⇒∠A = ∠B
(ii) ∠A + ∠D = ∠B + ∠C = 180° [Angels on the same side of transversal]
⇒∠A + ∠D = ∠A + ∠C ( ∠A = ∠B)
⇒∠D = ∠C
(iii) In ΔABC and ΔBAD,
AB = AB [Common]
∠DBA = ∠CBA 
AD = BC [Given]
Thus, ΔABC ≅ ΔBAD by SAS criteria.
(iv) Diagonal AC = Diagonal BD by C.P.C.T.
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Thanks......
Hope this Helps you....
Please mark it as Brainliest Answer........
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