Question

hey please provide solutions ...

55,56,57,58​

Answer 1

Answer:

58)option c

Explanation:

by the lose of 55.9% we will get the formula Na2So4. 10H2O

Answer 2

Answer:

58) c

Explanation:

mass of Na2SO4=142

mass of Na2SO4.xH2O=142+18x

then percentage of remaining wieght= 100-mass lost

=44%

therefore,

44/100(142+18x) =142

6248+792x=14200

then x=10

56)c 2PH3->2P+3H2

1mole=22.4L

so ,2mole=44.8L

2moleP+3moleH2=67.2L+44.8L=112

hence,

444.8=>112

0.1=>x

then x=0.25L=250mL

then dV=Vf-Vi=250-100=150mL