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question 14
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Hii There!!!
Given points (k,3) , (6, -2) and ( -3,4) are collinear.
So, area of triangle formed by these points will be equal to 0.
=) 1/2 | k (-2-4) + 6 ( 4-3) -3 (3+2) | = 0
=) -6k + 6 - 15 =0
=) k = -3/2
________________________
Hope it helps
Given points (k,3) , (6, -2) and ( -3,4) are collinear.
So, area of triangle formed by these points will be equal to 0.
=) 1/2 | k (-2-4) + 6 ( 4-3) -3 (3+2) | = 0
=) -6k + 6 - 15 =0
=) k = -3/2
________________________
Hope it helps
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