Hey !!!
Please solve the Question refer to attachment !!
_______________________
Step by step Solution needed !!!
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siddhartharao77:
Bro, I got x value as x = 1/y- 2? is it correct?
Answers
Answered by
8
Final Answer : 2 + 2√2
By using eq. of log.
![log(x - 2) + log(y) = 0 \\ = > (x - 2)y = 1 \\ log(x - 2) + log(y) = 0 \\ = > (x - 2)y = 1 \\](https://tex.z-dn.net/?f=+log%28x+-+2%29+%2B+log%28y%29+%3D+0+%5C%5C+%3D+%26gt%3B+%28x+-+2%29y+%3D+1+%5C%5C+)
By squaring and solving second equation we get,
(y-2)x = 1
Then, substitute value of
Now,
substitute value of y= 1/(x-2) ,
we get quadratic
x^2-2x-1=0
Solve this
these equations
x = 1-√2 and y = 1-√2
And x = 1 + √2 and y = 1 + √2
We reject first solution since,
x > 2
So, finally
x + y = 2 + 2√2
By using eq. of log.
By squaring and solving second equation we get,
(y-2)x = 1
Then, substitute value of
Now,
substitute value of y= 1/(x-2) ,
we get quadratic
x^2-2x-1=0
Solve this
these equations
x = 1-√2 and y = 1-√2
And x = 1 + √2 and y = 1 + √2
We reject first solution since,
x > 2
So, finally
x + y = 2 + 2√2
Answered by
3
howdy!!
your answer is in this pic.
value of x is 1+√2
so , x +y = x + x = 1+√2+1+√2 = 2+2√2
option (C) is right
hope it help you
your answer is in this pic.
value of x is 1+√2
so , x +y = x + x = 1+√2+1+√2 = 2+2√2
option (C) is right
hope it help you
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