Question

Hey, please solve this question...​

Answer 1

p(x)=2x

2

+kx+4 and g(x)=x+2

Zeroes of g (x) = x + 2 = 0

x = - 2

Now putting x = -2 in p ( x )

\begin{gathered}\large \text{$p(x)=2x^2 + kx + 4$}\\\\\\\large \text{$p(-2)=2(-2)^2 + k\times-2 + 4=0$}\\\\\\\large \text{$p(-2)=2\times4-2k+ 4=0$}\\\\\\\large \text{$12-2k=0$}\\\\\\\large \text{$12=2k$}\\\\\\\large \text{$k=6$}\end{gathered}

p(x)=2x

2

+kx+4

p(−2)=2(−2)

2

+k×−2+4=0

p(−2)=2×4−2k+4=0

12−2k=0

12=2k

k=6

Thus we get k = 6

Answer 2

Answer:

as x+2 is the factor of this equation

x= -2

put this value in equation

$2( { - 2)}^{2} + k( - 2) + 4$

$8 + - 2k + 4$

$12 - 2k = 0$

$- 12 \div - 2 = k$

$k = 6$

here is your answer