Math, asked by Anandboxer1107, 7 months ago

hey please tell fast
question 2 e ​

Attachments:

Answers

Answered by anjali7476
0

Step-by-step explanation:

(9.1)^2 = (9.0 + 0.1)^2

by applying identity (a+b)^2 = a^2 + b^2+2ab

put a = 9 ,b= 0.1

= 9^2 + 0.1^2 +2×9×0.1

= 81+0.01+1.8

= 82.81 ( answer)

hope this will helpful.

Answered by aryastuti2005
0

Answer:

Using the identity:

(a+b)^2 = a^2 + b^2 + 2ab

(9.1)^2

= (9 + 0.1)^2

= (9)^2 + (0.1)^2 + 2×9×0.1

= 81 + 0.01 + 01.80

= 81 + 01.81

= 82.81

Step-by-step explanation:

Hope it helps you.....

Similar questions